Finding location of CPA(Closest point of approach) of two ships using MATLAB code
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Hello.
My sample data is constructed the structure type of Matlab.
My data description is as follows;
The contents of sample data are ship’s data(date, time, longitude, latitude, speed, course) according to each ship id(MMSI).
The time interval of ship’s location is 2~35 second(less than 180 second).
So, that’s why ship’s data was interpolated per second.
The interpolated data was changed to bigger size than the original data.
I shared you my interpolated data, matlab function and powerpoint on google drive.
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The CPA means as follows;
An estimated point in which the distance between two ships. abbreviated CPA(Closest Point of Approach).
The estimate is used to evaluate the risk of a collision of two ships.
I shared one video recording file for explanation of CPA concept on google drive.
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You can see that as time goes by, CPA and TCPA changed on video file.
I have a matlab algorithm(function) about CPA. The algorithm was made from a journal.
I attatched an algorithm function about CPA.
My data is 250 ships.
Example
May first, 2014
If No.1 ship and No.2 ship in same date and time, I want to calculate DCPA, TCPA and range using my algorithm function.
And then, I want to select latitude and longitude for plotting location which is risk of collision of two ships.
(criterion lower than DCPA 0.15 nautical mile and lower than TCPA 3 minute).
...
No.1 and No.250 should be calculated DCPA, TCPA and range.
And then, I want to select latitude and longitude for plotting location which is risk of collision of two ships.
No.2 and No.3 should be calculated DCPA, TCPA and range.
And then, I want to select latitude and longitude for plotting location which is risk of collision of two ships.
...
No.2 and No.250 should be calculated DCPA, TCPA and range.
And then, I want to select latitude and longitude for plotting location which is risk of collision of two ships.
...
No.249 and No.250 should be calculated DCPA, TCPA and range.
And then, I want to select latitude and longitude for plotting location which is risk of collision of two ships.
May second, 2014 => same procedure.
May third, 2014 => same procedure.
...
last day
My purpose of this study is to find where is risk area of collision of two ships.
I have big data which is bigger than 4.0GB.
So, please should be considered speed for execution.
Is there anyone coding my project?
Hi! My name is Fernando Téllez. I am a senior year student of electrical engineering at Universidad Simón Bolívar (USB), one of the most prestigious universities in my country (Ranked 34° at the QS University Rankings: Latin America 2015).
I code using matlab ON A DAILY BASIS to solve any kind of engineering, logical, statistical and mathematical problem.
I bid to this project that let you know that your equation for finding distance of two ships is completely wrong. The equations in your matlab file is for Cartesian coordinate system, not spherical.
Also you have interpolated the data so you have information for every second and it is not necessary to find the time of nearest point by the equations you are written
What accuracy do you want for time an distance.
Mehrzad
Hello,
I can do this project. I am expert in Matlab. I have done no of project on Matlab. Please open your chat box for more discussion.
Area of Interest: Image Processing, Speech & Pattern reorganization, Signal Processing, wireless sensor network, routing protocol, electrical & electronics engineering and communication system.